For the first equation,
I used the slope intercept form y=mx+b, where m is the slope and b is the y-intercept, to get the y-intercept as 3. I then substitued 0 in for y to get the x-intercept as -3/5
For the second equation,
I used the quadratic function form y=ax^2+bx+c, where c is the y-interecept and -b/2a is the x-intercept. Thus, I got 4 as the y-intercept and -2 as the x-intercept.
Therefore,
1. x-intercept = -3/5
y-intercept = 3
2. x-intercept = -2
y-intercept = 4