We can set this up using a diagram.
- Code:
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Red Blue Green
/ \ / \ / \
A B A B A B
/ \ / \ / \ / \ / \ / \
C D C D C D C D C D C D
(A = blue, B = black, C = green, D = yellow. Sorry about the formatting!)
Then we count the bottom row, and find there are 12 solutions.
Alternatively, we can set this problem up with algebra. To find the number of choices in a problem like this, you just multiply the number of choices together, so:
3 x 2 x 2 = 12
Therefore, there are 12 decisions.