BhandarkarA
Posts : 85
Join date : 2009-09-11
 | | Subject: Algebra Puzzle II Wed Dec 30, 2009 8:23 pm | |
| If the area of a rectangle is 60 and it's perimeter is 100, find the length of it's diagonal. Express in radical form. | |
|
AK_Kadaveru
Posts : 28
Join date : 2009-10-20
| | Subject: Re: Algebra Puzzle II Sat Jan 02, 2010 8:16 pm | |
| - BhandarkarA wrote:
- If the area of a rectangle is 60 and it's perimeter is 100, find the length of it's diagonal. Express in radical form.
The answer is - Spoiler:
the square root of 2380
Explanation: - Spoiler:
if l is the length and w is the width, then lw=60 and 2(l+w)=100 so l+w=50. lets square that equation. (l+w)2=502or l2+w2+2lw=2500. since lw is 60, l2+w2+2(60)=2500 so l2+w2=2380. the length of the diagonal is sqrt(l2+w2) so the diagonal is the square root of 2380
| |
|
